3[7-2(7x-4)]=-42x+45

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Solution for 3[7-2(7x-4)]=-42x+45 equation: 


Simplifying
3[7 + -2(7x + -4)] = -42x + 45

Reorder the terms:
3[7 + -2(-4 + 7x)] = -42x + 45
3[7 + (-4 * -2 + 7x * -2)] = -42x + 45
3[7 + (8 + -14x)] = -42x + 45

Combine like terms: 7 + 8 = 15
3[15 + -14x] = -42x + 45
[15 * 3 + -14x * 3] = -42x + 45
[45 + -42x] = -42x + 45

Reorder the terms:
45 + -42x = 45 + -42x

Add '-45' to each side of the equation.
45 + -45 + -42x = 45 + -45 + -42x

Combine like terms: 45 + -45 = 0
0 + -42x = 45 + -45 + -42x
-42x = 45 + -45 + -42x

Combine like terms: 45 + -45 = 0
-42x = 0 + -42x
-42x = -42x

Add '42x' to each side of the equation.
-42x + 42x = -42x + 42x

Combine like terms: -42x + 42x = 0
0 = -42x + 42x

Combine like terms: -42x + 42x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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